Solve for x: f(g(x))=30 | Factor & Simplify: (x+5)^2+6(x+5)(x-4)

  • Thread starter Nikola Tesla
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In summary, to solve for x if f(g(x))=30, you can substitute u = √(x+6) and solve the quadratic equation u^2 - 3u = 30. To factor and simplify the expression (x+5)^2+6(x+5)(x-4), you can factor out (x+5) to get (x+5)(x+5+6(x-4)).
  • #1
Nikola Tesla
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If f(x)=x^2-3x and g(x)=in square root of x+6, solve for x if f(g{x))=30

Also, factor this expression and simplify if necessary: (x+5)^2+6(x+5)(x-4)

Thanks.
 
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  • #2
What have you tried so far? What are you having trouble with?
 
  • #3
For the first one, I got to, x+6 - 3(square root of x+6) = 30 lol

I don't know what to do next, I think I'm supposed to get rid of the three, but I'm not sure how.
 
  • #4
Nikola Tesla said:
For the first one, I got to, x+6 - 3(square root of x+6) = 30 lol

I don't know what to do next, I think I'm supposed to get rid of the three, but I'm not sure how.

You can make a substitution to end up with a quadratic equation,

let u = square root of (x+6)

so you end up with

u2 - 3u = 30

You can then solve for u and thn substitue back to solve for x.
 
  • #5
Nikola Tesla said:
Also, factor this expression and simplify if necessary: (x+5)^2+6(x+5)(x-4)
For the second one, you may want to factor (x + 5) out.
(x + 5)2 + 6(x + 5)(x - 4) = (x + 5) (x + 5 + 6(x - 4)) = ...
Can you go from here? :)
 

FAQ: Solve for x: f(g(x))=30 | Factor & Simplify: (x+5)^2+6(x+5)(x-4)

What is the equation to solve for x?

The equation to solve for x is f(g(x))=30, which is given in the problem.

What does it mean to factor and simplify an equation?

Factoring an equation means breaking it down into smaller parts that can be multiplied together to get the original equation. Simplifying an equation means reducing it to its most basic form.

What are the steps to factor and simplify (x+5)^2+6(x+5)(x-4)?

The first step is to expand the equation using the FOIL method, which gives us x^2+10x+25+6x^2-6x-120. Then, we can combine like terms to get 7x^2+4x-95. Finally, we can factor the equation to get (x-5)(7x+19).

How do I solve for x in (x+5)^2+6(x+5)(x-4)=30?

To solve for x, we can use the factored equation (x-5)(7x+19)=30 and set each factor equal to 0. This gives us x-5=0 and 7x+19=0. Solving for x in each equation gives us x=5 and x=-19/7. Therefore, there are two solutions for x.

Can this equation be solved using any other methods?

Yes, this equation can also be solved by expanding and simplifying the equation to get a quadratic equation in standard form (ax^2+bx+c=0). Then, you can use the quadratic formula or factor the equation to find the solutions for x.

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