MHB Solve Fun Logic Puzzle: 111 People & 4 Jewels

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    Fun Logic Puzzle
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In a competition with 111 participants, each guessing the contents of 4 opaque boxes containing different jewels, the distribution of correct guesses is analyzed. Out of the competitors, 9 guessed all jewels incorrectly, 15 guessed one correctly, and 25 guessed two correctly. The puzzle seeks to determine how many participants guessed exactly three or four jewels correctly. The discussion hints at the possibility of participants guessing the same jewel more than once, which could affect their chances of being correct. The solution involves logical deduction based on the given data about the guesses.
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There are 111 people in a competition. The competition has 4 boxes and 4 jewels. Each box is identical and is completely opaque (i.e. you cannot see inside the box once it is closed). The jewels are all different: diamond, ruby, emerald and topaz. Everyone in the competition knows this. The host (who is NOT one of the 111 taking part), places one jewel in each box and then seals the boxes and writes a letter on each box: A, B, C and D - all done WITHOUT any of the 111 competitors watching. The competitors are then asked to guess which jewel is in which box.

-9 people get all 4 of their guesses wrong
-15 people guess exactly one jewel correctly
-25 people guess exactly 2 jewels correctly

How many people:
a) guess exactly 3 jewels correctly
b) guess exactly 4 jewels correctly

Bit of a hey, I'm back... again... puzzle!
 
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If you want a hint, feel free to ask! :)
 
My solution:

Since it is impossible to guess only 3 correctly, that leaves the remaining 62 to have guessed all 4 correctly.
 
MarkFL said:
My solution:

Since it is impossible to guess only 3 correctly, that leaves the remaining 62 to have guessed all 4 correctly.
[sp]Unless one or more people guessed twice of the same jewel, so they would have a slightly higher chance of guessing one of those right. But it[/sp]
 
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