Solve IVP DE: x'=-3x+4y-2, y'=-2x+3y, x(o)=-1, y(o)=3

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The discussion focuses on solving the initial value problem (IVP) for the system of differential equations x' = -3x + 4y - 2 and y' = -2x + 3y, with initial conditions x(0) = -1 and y(0) = 3. One participant attempts to derive a solution but encounters an error in their calculations, particularly in substituting x' with x. Another participant suggests reformulating the problem in matrix form to solve it as a system of linear equations, which may simplify the process. The conversation highlights the importance of accurate substitutions and the potential benefits of using matrix methods in solving differential equations. Overall, the thread emphasizes problem-solving strategies in differential equations.
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Thanks for the help.

Homework Statement



Solve the IVP: x'=-3x+4y-2, y'=-2x+3y, x(o)=-1, y(o)=3


The Attempt at a Solution


x''=-3x'+4y'
x''=-3x+4(-2x+3y)=-3x-8x+12y
y=(x'+3x+2)/4
x''=-3x-8x+12((x'+3x+2)/4)
x''-x=6
xgeneral=xh+xp
Xg=Ce^t+Ce^-t-6
Yg=1/4(Ce^t-Ce^-t+3Ce^t+3Ce^t)
Yg=Ce^t+1/2(Ce^-t)-4
x(t)=
y(t)=
 
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there's an error in your first line, where you've replaced x' with x

why not write in matrix form and solve as a system of linear equations
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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