Solve Work on Inclined Plane for m1, a, h, m2, uk

In summary, the conversation involved calculating the work done by various forces on blocks placed on an inclined plane and connected by a cord. The coefficient of kinetic friction was given, along with other parameters such as mass, angle of incline, and distance. The final speed of the blocks was also calculated. In another conversation, the same calculations were done for a system of connected blocks on an incline, with the additional task of solving for the coefficient of kinetic friction in terms of the given parameters. The use of proper punctuation and following forum guidelines was suggested in order to improve communication and avoid hijacking existing threads.
  • #1
oreosama
51
0

Homework Statement


A block of mass m1 is placed on an inclined plane with slope angle a and is connected to a second hanging block of mass m2 by a cord passing over a small frictionless pulley the coefficient of kinetic friction is uk the system is released from rest with block m2 dropping a distance h.

given m1, a, h, m2, uk
calc the work due to each of the forces on block 1 in moving h
calc the work due to each of the forces on block 2 in moving h
calc the total work on the sys and final speed of the blocks

Homework Equations



w = F*d

The Attempt at a Solution



http://i.imgur.com/IxtPw.png

for block1

Wg = -h*mg*sin a

Wt1 = hT

Wn=0

Wff = -h*uk*mg*cos a

Wtot = hT - *mg*sin a - h*uk*mg*cos a


for block2

Wg = mgh

Wt = -hT

Wtot = mgh - hT


hT - *mg*sin a - h*uk*mg*cos a + mgh - hT = 1/2*m*Vf^2 + 1/2*m2*Vf^2 - 0 (start from rest)

sqrt( 2/(m1+m2) * (mg*sin a - h*uk*mg*cos a + mgh)) = Vf



----

blocks a, b, c are connected as shown. block a,b,c have same mass m and coefficient of kinetic friction between each block and the surface is uk. block c descends with constant velocity. use 30 for angle of incline. given m h uk determine

work due to forces on A moving h
work due to forces on B moving h
work due to forces on C moving h
solve for uk in terms of the other givens for the system to move at constant speed



http://i.imgur.com/DtwxJ.png


block A

Wff= -uk*mg*h

Wt= T1*h

block B

Wt2 = T2*h
Wg = -mg*sin a*h
Wff= -uk*mg*cos a * h
Wt1 = -T1*h

wtot = T2*h - mg*sin a * h - uk*mg*cos a * h - T1* h

block C

Wg = mg*h
Wt2 = -T2*h

Wtot = mg*h - T2*h


T1*h - uk*mg*h + T2*h - mg*sin a * h - uk* mg* cos a * h - T1*h + mg*h - T2*h = 0(constant speed implies vf v0 are the same meaning no change in kinetic energy right??)

-uk*mg*h - uk*mg*cos a * h = mg*sin a * h - mg*h

-uk - uk*cos a = sin a - 1

-uk(1 + cos a) = sin a - 1
uk = - (sin a - 1/ (1+cos a))

uk = 1/2 / (2+sqrt(3))/2

uk = 1/(2+sqrt(3))






want to be sure I am not doing anything horribly wrong thanks for any help.
 
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  • #2
oreosama said:

Homework Statement


A block of mass m1 is placed on an inclined plane with slope angle θ and is connected to a second hanging block of mass m2 by a cord passing over a small frictionless pulley. The coefficient of kinetic friction is μk. The system is released from rest with block m2 dropping a distance h.

given m1, θ, h, m2, μk
calc the work due [STRIKE]to[/STRIKE] by each of the forces on block 1 in moving h
calc the work due to each of the forces on block 2 in moving h
calc the total work on the sys and final speed of the blocks

http://i.imgur.com/IxtPw.png
...

----

blocks a, b, c are connected as shown. block a,b,c have same mass m and coefficient of kinetic friction between each block and the surface is uk. block c descends with constant velocity. use 30 for angle of incline. given m h uk determine

work due to forces on A moving h
work due to forces on B moving h
work due to forces on C moving h
solve for uk in terms of the other givens for the system to move at constant speed

http://i.imgur.com/DtwxJ.png
...

want to be sure I am not doing anything horribly wrong thanks for any help.
Wow! A little bit of punctuation, etc. sure helps ! ...along with a few other changes.
 
  • #3
didnt seem to be an issue on other posts, sorry
 
  • #4
oreosama said:
didnt seem to be an issue on other posts, sorry
Do you mean, in your other posts?

In many of those you did, at least, use periods.

You probably should take a bit of time to read rules for posting in this Forum. Here are two short excerpts.
General Posting Guidelines
...Pay reasonable attention to written English communication standards. This includes the use of proper grammatical structure, punctuation, capitalization, and spelling. ...

Do not hijack an existing thread with off-topic comments or questions--start a new thread.
 
  • #5
are you having trouble interpreting what I've typed? clearly not or you wouldn't be capable of correcting it by replacing one word and telling me to use more periods. I think that fulfills reasonable english communication.

now read the last sentence of your post. do you not see the irony?
 

Related to Solve Work on Inclined Plane for m1, a, h, m2, uk

1. What is the formula for solving work on an inclined plane?

The formula for solving work on an inclined plane is W = Fd = mg(sinθ)h, where W is the work done, F is the force applied, d is the distance covered, m is the mass of the object, g is the acceleration due to gravity, θ is the angle of inclination, and h is the height of the inclined plane.

2. How do you determine the value of m1 and m2 in the formula?

m1 and m2 in the formula represent the masses of the two objects on the inclined plane. To determine their values, you can weigh the objects using a scale or obtain their masses from a given problem or experiment.

3. What is the role of uk in the formula?

uk represents the coefficient of kinetic friction between the two objects on the inclined plane. It is a constant that depends on the nature of the surfaces in contact. It is used to calculate the force of friction, which is a resistive force that affects the work done on the inclined plane.

4. How does the angle of inclination affect the work done on an inclined plane?

The angle of inclination, θ, plays a significant role in the calculation of work on an inclined plane. As the angle increases, the work done also increases. This is because the force applied in the direction of motion increases, resulting in a larger distance covered and thus, more work done.

5. Can the formula be used for objects of any shape?

Yes, the formula for solving work on an inclined plane can be used for objects of any shape as long as they are treated as point masses. This means that the mass of the object is concentrated at a single point, usually at the center of mass. This simplifies the calculation and makes the formula applicable to a wide range of objects.

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