Solving for Driving Point-Impedance: Techniques and Simplification

  • Thread starter Thread starter Wilson Lin
  • Start date Start date
AI Thread Summary
To determine the driving point-impedance, mesh analysis is not strictly necessary; alternative techniques can be employed. Simplifying the circuit using parallel and series combinations can effectively yield the equivalent two-terminal circuit. This approach allows for the calculation of the driving point impedance without complex analysis. Participants are encouraged to share their work for further guidance. Understanding these simplification techniques is crucial for solving related problems efficiently.
Wilson Lin
Messages
1
Reaction score
0
To find the driving point-impedance do I need to do mesh analysis?
Or is there other techniques to solve the problem?
 

Attachments

  • Screen Shot 2017-03-08 at 2.32.59 PM.png
    Screen Shot 2017-03-08 at 2.32.59 PM.png
    6.8 KB · Views: 590
Physics news on Phys.org
Wilson Lin said:
To find the driving point-impedance do I need to do mesh analysis?
Or is there other techniques to solve the problem?
Welcome to the PF. :smile:

I moved your thread from the EE forum to the Homework Help forum because it is askig about schoolwork. Please post schoolwork-type questions here in the HH forums going forward.

On your question, this circuit is simple enough that you can use parallel and serial combination simplification to form the equivalent 2-termianl circuit. That will give ou the drive point impedance. Can you show us that work?
 
Thread 'Have I solved this structural engineering equation correctly?'
Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...

Similar threads

Replies
5
Views
3K
Replies
2
Views
2K
Replies
7
Views
3K
Replies
1
Views
2K
Replies
12
Views
2K
Replies
2
Views
1K
Replies
35
Views
3K
Replies
13
Views
2K
Replies
1
Views
2K
Back
Top