Solving for x: x^2 + (x-a)(a+1)/(x-a)

  • MHB
  • Thread starter prasadini
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In summary, solving for x in an equation involves finding the value or values of x that make the equation true. This is important for solving problems and equations involving variables. To solve for x, you can use the quadratic formula or factor the equation. Quadratic equations can have two, one, or no solutions. If you are unable to solve for x, it may mean that there are no real solutions. Substituting values for a can help find specific solutions for x and understand the impact of different values of a.
  • #1
prasadini
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x^{2} + (x - a) (a+1)/(x-a)
 
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  • #2
prasadini said:
x^{2} + (x - a) (a+1)/(x-a)

Hi prasadini,

What is the goal here? There is no equals sign in the above, so if the goal to simplify? Is there something missing?
 

FAQ: Solving for x: x^2 + (x-a)(a+1)/(x-a)

1. What is the purpose of solving for x in this equation?

The purpose of solving for x in this equation is to find the value or values of x that make the equation true. This is important in order to solve problems and equations involving variables.

2. How do I solve for x in this equation?

To solve for x in this equation, you can use the quadratic formula or factor the equation if possible. First, rearrange the equation to have all terms on one side and 0 on the other side. Then, plug in the values for a and solve for x using the appropriate method.

3. Can this equation have more than one solution for x?

Yes, this equation can have more than one solution for x. This is because it is a quadratic equation, meaning it has a squared term. Quadratic equations can have two solutions, one solution, or no solutions at all.

4. What happens if I cannot solve for x in this equation?

If you are unable to solve for x in this equation, it may mean that the equation has no real solutions. This can happen if the equation has imaginary solutions, or if there is an error in the original equation.

5. Can I substitute values for a and solve for x in this equation?

Yes, you can substitute values for a and solve for x in this equation. This can help you find specific solutions for x, as well as understand how different values of a affect the overall equation.

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