Solving Ladder Operator Problem w/ 4 Terms

AI Thread Summary
The discussion revolves around solving the expectation value of px4 in the ground state of a harmonic oscillator using ladder operators. The original poster struggles with the complexity of four ladder operators in a term, contrasting it with simpler cases involving two operators. They receive advice on applying the properties of ladder operators and the implications of Schrödinger's equation. The suggestion to utilize the evenness or oddness of the wave functions and potential simplifies the integral significantly. Ultimately, the original poster finds success using the recommended method, indicating clarity in their understanding.
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Homework Statement



I have been given the following problem -
the expectation value of px4 in the ground state of a harmonic oscillator can be expressed as
<px4> = h4/4a4 {integral(-infin to +infin w0*(x) (AAA+A+ + AA+AA+ + A+AAA+) w0 dx}

I think I know how to proceed on other examples, but my given examples only have ladder operators with two terms, i.e. AA+ or A+A.
I can then use the commutation relation, AA+ - A+A =1 to remove them.

what has stuck me here is the four ladder operators in a term. I'm totally unsure on how to proceed!

any advice would be greatly appreciated!
 
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Do you know what A and A+ do to eigenstates? A+ψn = sqrt(n+1)ψn+1 and Aψn=sqrt(n)*ψn-1, so you can just keep applying the appropriate operator until you get down to a constant multiple of the eigenfunction.
 
I'd like to suggest a completely different method. Use two things here

1. Schrodinger's equation, which can be rearranged to form
p^2\psi = c (E-V)\psi where c is some constant

2. The fact the p is hermitian

<br /> \left&lt;p^4\right&gt; = \left&lt;\psi |p^4|\psi\right&gt; = \left&lt;p^2\psi|p^2\psi\right&gt; = c^2 \left&lt;(E-V)^2\right&gt;<br />

The last part of the above integral can be greatly simplified using the evenness or oddness of the functions \psi and V. Try it.
 
Many thanks for both your replies.

I think ideasrule's method was the one I am supposed to follow - managed to get the right answer! A few more clouds lifted...
thanks again
 
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