Solving Schrodinger Eq.: Quantum #s for n=0,1,2

AI Thread Summary
The discussion revolves around solving the Schrödinger equation and identifying the quantum numbers for n=0, 1, and 2. It clarifies that the principal quantum number n starts from 1, as n=0 is not valid in this context. For n=1, the possible values for the orbital quantum number l is 0, and the magnetic quantum number m1 can only be 0, while the spin quantum number Ms can be either -1/2 or 1/2. Participants express confusion about the question's requirements and seek clarification on how to approach the problem. The thread emphasizes the importance of starting from n=1 for valid quantum number assignments.
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Homework Statement


The solution of the Schrodinger equation for atom depends on four quantum numbers: the principal n, the orbital l, magnetic m1, and the spin Ms
n = 1, 2, 3, 4, ... (integers)
l = 0, 1, 2, ... (n-1)
m1 = -1, -1+1,...0...1-1, 1
Ms = -1/2, 1/2
List all possible values of n, l, m1, and ms for n= 0,1,2

Homework Equations





The Attempt at a Solution


I actually have no clue what the question is asking.. It is exactly how the professor typed it up as.. Can someone help me please?
 
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Can someone give me a hint on how to figure out the solution?
 
Begin with n=0. What are then the possible values for the other 3 quantum numbers ? Then the same question for n=1, etc.

EDIT: Sorry, n=1, of course. :D So n=1, what's l equal to ?
 
Last edited:
How is this in advanced physics?
 
Moderator's note: I have moved this thread to Introductory Physics. In the future, please post questions of this level in Introductory Physics.

By the way, there is a problem with n=0. I would start with n=1 instead.
 
sandy.bridge said:
How is this in advanced physics?

Sorry, I'm new to the forum..
 
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