Solving sqrt (Y+6) - sqrt (3y) = 3

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To solve the equation sqrt(Y+6) - sqrt(3y) = 3, it is necessary to square both sides of the equation twice. The first squaring isolates one square root, leading to the equation y + 6 + 3y - 2sqrt((y+6)(3y)) = 9. After isolating the remaining square root, squaring again will yield a quadratic equation. It is important to check that the solutions obtained are greater than zero to ensure they are valid. This method will help in accurately completing the homework.
perpetual-burn
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Hey guys,
I was wondering how to solve this equation. I tihnk I got it, but I want to make sure so I don't go on doing all of my homework wrong.

Question: sqrt (Y+6) - sqrt (3y) = 3

I forget if I have to sqaure each separate or the whole left side as FOIL. Please let me knwo asap so I can finish homeowkr :) Again, thanks so much!

-Phil
 
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U'll have to square twice.And each time separate a sqrt in one side of the equation.

\sqrt{y+6}-\sqrt{3y}=3\Rightarrow y+6+3y-2\sqrt{\left(y+6\right)3y}=9

and then isolate in one member of the equation that sqrt and then square again.

Daniel.
 
Ok, waht i tohught :) Thanks Dan.
 
I hope u can solve the quadratic that will follow.And to check whether the solutions u get are larger than 0...

Daniel.
 
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