- #1
Steve10
- 14
- 0
A car rental company receives cars at n = 1000 cars/year for the first 5 years and none thereafter.
The pdf for retiring a car is,
Show that after 6 years cars are being retired from the scheme at approxiamtely 11 per week.
To answer that I did,
N = int[t1 to t2] t*p(t) dt
where
t1 = 6 (years)
t2 = 6 1/52 (years)
and
N would be the number of retired cars during that week.
I thought that was how I was supposed to do it. Is that correct ?
When I worked out that integral, I got N = 0.0134.
How do I get 11 as the answer ?
Where does the n = 1000 come into it, if at all ?
The pdf for retiring a car is,
Code:
p(t) = (1/5)(1 - exp(-t/3)) , 0<t<5
= (1/5)(exp[-(t-5)/3] - exp(-t/3)) , t > 5
Show that after 6 years cars are being retired from the scheme at approxiamtely 11 per week.
To answer that I did,
N = int[t1 to t2] t*p(t) dt
where
t1 = 6 (years)
t2 = 6 1/52 (years)
and
N would be the number of retired cars during that week.
I thought that was how I was supposed to do it. Is that correct ?
When I worked out that integral, I got N = 0.0134.
How do I get 11 as the answer ?
Where does the n = 1000 come into it, if at all ?