dionysian
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Homework Statement
Solve the euqation dP/dt = k(M - P)P to show that it equals: P(t) = (MP_{0}) /( P_{0} + (M - P_{0})e^{-kMt})
Homework Equations
The Attempt at a Solution
\[ \int \frac {dP} {P(M - P)}\] = k \int dt \
\frac {1} {M}\ \ln( \frac {P} {M - P}) + C = Kt + C
I combine the constants of integration... i can do this right?
Then i get rid of the log by taking the exponent of both sides.
P/(M - P) = e^{mkt + c}
I then turn e^{c} into P_{0}
Next i divide through by (M - P)
P = (M - P)P_{0}e^{mkt}
next i combine the P then divide through by the remainder.
P = (mP_{0}e^{mkt})/(1 + P_{0}e^{mkt})
and i end up with:
P = (mP_{0})/(e^{-mkt} + P_{0})
In the equation i am suppose to get i don't see how there could possibly be three terms in the denominator.
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