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paulmdrdo1
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1. A’s rate of doing work is three times that of B. On a given day A and B work together for 4 hours; then B is called away and A finishes the rest of the job in 2 hours. How long would it take B to do the complete job alone?
if I let x = B's rate of work and 3x = A's rate of work, I'll have this equation,
$\displaystyle 4\left(\frac{1}{x}+\frac{1}{3x}\right)+2\frac{1}{x}=1$
then, $x=7\frac{1}{3}$ and $3x=22$ is this correct?
2. A and B working together can complete a job in 6 days. A works twice as fast as B. How
many days would it take each of them, working alone, to complete the job?
let x = required time for B to finish a job alone, 2x = required time for A to finish a job alone
$\displaystyle 6\left(\frac{1}{x}+\frac{1}{2x}\right)=1$
the answer is x = 9 days for B, and 2(9)= 18 days for A.
but this doesn't make sense. if A is twice as fast as B it will take A lesser time to complete a job than B.
please help.
if I let x = B's rate of work and 3x = A's rate of work, I'll have this equation,
$\displaystyle 4\left(\frac{1}{x}+\frac{1}{3x}\right)+2\frac{1}{x}=1$
then, $x=7\frac{1}{3}$ and $3x=22$ is this correct?
2. A and B working together can complete a job in 6 days. A works twice as fast as B. How
many days would it take each of them, working alone, to complete the job?
let x = required time for B to finish a job alone, 2x = required time for A to finish a job alone
$\displaystyle 6\left(\frac{1}{x}+\frac{1}{2x}\right)=1$
the answer is x = 9 days for B, and 2(9)= 18 days for A.
but this doesn't make sense. if A is twice as fast as B it will take A lesser time to complete a job than B.
please help.
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