Solving Vector Problems: Need Help Figuring it Out

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The discussion revolves around solving a vector problem involving two beetles running on flat sand. Beetle 1's movements are calculated using vector addition, resulting in a total displacement of 2.95m at an angle of 37.14 degrees. The second beetle's required displacement is determined by subtracting Beetle 1's resultant vector from its first run. The error identified was in incorrectly adding all vectors instead of using the correct approach of A + B - C to find the second run's magnitude and direction. The final answers for the second beetle's run are 0.84m in magnitude and 79 degrees in direction.
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Hey guys, I need your help figuring out what I am doing wrong.

Two beetles run across flat sand, starting at the same point. Beetle 1 runs 0.5m due east, then 0.80m at 30 degrees north of due east. Beetle 2 also makes two runs; the first is 1.6m at 40 degrees east of due north. What must be (a) the magnitude and (b) the direction of its second run if it is to end up at the new location of beetle 1?

40 degrees east of due north = 50 degrees

vector A = 0.5m
vector B = 0.8m
vector C = 1.6m

A = .5i + 0j
B = (.8cos(30))i + (.8sin(30))j
C = (1.6cos(50))i + (1.6sin(50))j

R = 2.35i + 1.78j
R = [2.35^2 + 1.78^2]^1/2 = 2.95m
arctan=(1.78/2.35)=37.14 degrees

Answer should be: (a) 0.84m (b) 79 degrees

What am I doing wrong here? Am I approaching it wrong?
 
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You aren't showing the crucial part of your work! What did you do with vectors A, B, and C after you got them?

The first beetle's total motion is A+ B, then second's is C so to arrive at the same place the second beetle must go A+B- C.
 
I was adding A + B + C. I see how logically that wouldn't make sense. Thanks I got the answer.
 
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