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atyy
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vanhees71 said:It's a bit strange to me to say the Schrödinger waves are in Hilbert space. It's simply a scalar complex valued field which describes waves, but just in the mathematical sense. It's not like the waves of a measurable field quantity like, e.g., the density of air or water (sound waves) or the electromagnetic field, but its physical meaning is given by the Born rule.
What the quantum mechanics is supposed to describe is, of course, given by the choice of the problem. If you have a single particle, you start by defining observables by assuming some operator algebra, heuristically taken from some classical analgous situation. Of course, you cannot derive this in a mathematical sense from anything, but you have to more or less guess it. What helps you, are symmetries and (Lie-)group theory to guess the right operator algebra. The self-adjoint operators live on a Hilbert space, and the rays in this Hilbert space represent the (pure) states. Then, if ##|\psi \rangle## is a normalized representant of such a ray, a wave function is given wrt. a complete basis, related to the determination of a complete set of compatible observables, ##|o_1,\ldots,o_n \rangle##, i.e.,
$$\psi(o_1,\ldots,o_n)=\langle o_1,\ldots o_n|\psi \rangle.$$
That's it. In my opinion there's no simpler way to express quantum theory than this. Admittedly it's very abstract und unintuitive, but that's the only way we have found so far to adequately describe (pretty comprehensively) the phenomena in terms of a pretty self-consistent mathematical scheme.
Yes, it's a bit strange, but that it's not wrong shows that there is nothing wrong with wave-particle duality. Again in non-rigourous QFT, the Fock space is still a particle space. Then if we take the Wilsonian viewpoint and accept a lattice regularization, the lattice is again QM, which is a particle space.