Special Relativity: Photoproduction of Mesons?

AI Thread Summary
The discussion centers on the photoproduction of K+ mesons through the reaction γ + p → K+ + Λ, focusing on whether either K+ or Λ can be at rest in the lab frame and determining the required photon energy. Participants highlight the importance of applying conservation laws for energy and momentum to solve the problem. One user expresses difficulty in manipulating the equations for conservation, suggesting a need for algebraic clarity. Another contributor recommends using momentum 4-vectors as an alternative method to simplify calculations. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


12-16 K + mesons can be photoproduced by the reaction γ + p → K+ + Λ where the initial proton is at rest in the lab. From the conservation laws, discover if it is possible for either the K+ or the Λ to be at rest in the lab, and for what photon energy (in terms of the particle masses) this could happen.

Homework Equations


E^2 = p^2c^2 + m^2c^4
p = mv
E = mc^2

The Attempt at a Solution


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I'm really stuck on this problem. It's probably more of an algebraic answer, because I believe I'm supposed to somehow get the two equations of energy and momentum conservation to have like terms and then combine them somehow, but I'm at a loss as to what to do. Any help is appreciated.
 
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I think you already have the equations.
Conservation of Momentum: \displaystyle{p_\gamma =p_\Lambda \Rightarrow E_\gamma =p_\Lambda c\Rightarrow E_\gamma ^2=E_\Lambda ^2-m_\Lambda ^2c^4}
If you combine this with the conservation of energy you have two equations and two uknowns, \displaystyle{E_\gamma } and \displaystyle{E_\Lambda}.

Another way to solve such problems without algebraic difficulties is by using the momentum 4-vector (also known as 4-momentum). In this problem the calculations are not so tough, because there are only two momenta, so the 4-momentum solution is not much different. But I think it's worth reading about this method, because sometimes it's really helpful.
 
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