Speed of two protons (I think an easy question)

  • Thread starter Thread starter iamkristing
  • Start date Start date
  • Tags Tags
    Protons Speed
AI Thread Summary
The discussion revolves around calculating the top speed of two protons released from rest at a distance of 1.500 nm apart. The relevant equations include F=ma and the kinetic energy formula involving electrostatic force. The user correctly calculated the speed using the mass and charge of the protons, arriving at a speed of approximately 9.59 x 10^3 m/s. A minor typo regarding the distance was noted, but the overall calculation process was confirmed as correct. The discussion concludes with validation of the user's approach to the problem.
iamkristing
Messages
33
Reaction score
0
[SOLVED] speed of two protons (I think an easy question)

Homework Statement



If you release two protons from rest 1.500nm apart, calculate the top speed, relative to you, that either proton will achieve.

Homework Equations



F=ma

ke^2/r=mv^2 where k=9.0e9 Nm^2/C^2 and e is the charge

The Attempt at a Solution



mass proton = 1.67e-27
charge proton = 1.60e-19

So just plug in and solve for v=

v= [(9e9)((1.6e-19)^2/(1.5e-19))/1.67e-27]^1/2

v=9.59e3 m/s

I just wanted to make sure the process I used for this problem was correct...

Thanks!
 
Physics news on Phys.org
Looks good.

Just one typo ( r = 1.5e-19 ? ), but you did use the right number in the calculation.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top