- #1
iamkristing
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[SOLVED] speed of two protons (I think an easy question)
If you release two protons from rest 1.500nm apart, calculate the top speed, relative to you, that either proton will achieve.
F=ma
ke^2/r=mv^2 where k=9.0e9 Nm^2/C^2 and e is the charge
mass proton = 1.67e-27
charge proton = 1.60e-19
So just plug in and solve for v=
v= [(9e9)((1.6e-19)^2/(1.5e-19))/1.67e-27]^1/2
v=9.59e3 m/s
I just wanted to make sure the process I used for this problem was correct...
Thanks!
Homework Statement
If you release two protons from rest 1.500nm apart, calculate the top speed, relative to you, that either proton will achieve.
Homework Equations
F=ma
ke^2/r=mv^2 where k=9.0e9 Nm^2/C^2 and e is the charge
The Attempt at a Solution
mass proton = 1.67e-27
charge proton = 1.60e-19
So just plug in and solve for v=
v= [(9e9)((1.6e-19)^2/(1.5e-19))/1.67e-27]^1/2
v=9.59e3 m/s
I just wanted to make sure the process I used for this problem was correct...
Thanks!