- #1
Richard_R
- 14
- 0
Hello All,
I am having to brush up on my stats for work and it's been a long time (>10yrs) since I've had to even think about this stuff. I could do with some help clarifying a specific point about standard errors and margin of error.
An example I am looking at from my old notes is this: the manager of an ice-cream shop wants to know the average amount of ice-cream his staff put into each ice-cream cone. If 50 samples are taken with an average (mean) of 10.3 ounces and a standard deviation of 0.6 ounces then what is the margin of error (MOE) at the 95% confidence level?
Now I think I've worked out the answer correctly:
MOE @ 95% CL = 1.96 x 0.6/SQRT50 = 0.17 ounces
I.e. MOE = 10.3 oz +/- 0.17 oz at 95% CL
However I am not totally sure how to interpet this result. Does this mean that if I redid the experiment again and again that 95% of the individual results in each sample would be within that range (10.3 +/- 0.17) or that the mean from each sample would be within that range, or both?
I think it's the sample means as standard errors and margins of error have to do with sample means (or proportions) but am not 100% sure...
Thanks!
-Rob
I am having to brush up on my stats for work and it's been a long time (>10yrs) since I've had to even think about this stuff. I could do with some help clarifying a specific point about standard errors and margin of error.
An example I am looking at from my old notes is this: the manager of an ice-cream shop wants to know the average amount of ice-cream his staff put into each ice-cream cone. If 50 samples are taken with an average (mean) of 10.3 ounces and a standard deviation of 0.6 ounces then what is the margin of error (MOE) at the 95% confidence level?
Now I think I've worked out the answer correctly:
MOE @ 95% CL = 1.96 x 0.6/SQRT50 = 0.17 ounces
I.e. MOE = 10.3 oz +/- 0.17 oz at 95% CL
However I am not totally sure how to interpet this result. Does this mean that if I redid the experiment again and again that 95% of the individual results in each sample would be within that range (10.3 +/- 0.17) or that the mean from each sample would be within that range, or both?
I think it's the sample means as standard errors and margins of error have to do with sample means (or proportions) but am not 100% sure...
Thanks!
-Rob