Steam Point Temp. Interval - check answer

[Quelsita]

QUESTION:
Suppose the numerical value of 492 is assigned to the ice point temperature $$\theta$$_ice=492.
a) Find the steam point temperature on this scale.

b) Calculate the temperature interval between the steam point and the ice point on
this scale.

SOLUTION a :
We know that the ratio $$\theta$$_ice/$$\theta$$_steam = 1.3661
and that $$\theta$$_steam - $$\theta$$_ice = 100

thus,

$$\theta$$_steam = (1.3661)($$\theta$$_ice)
$$\theta$$_steam = (1.3661) (492)
$$\theta$$_steam = 671.12

SOLUTION b:
If $$\theta$$_ice=492 and
$$\theta$$_steam=672.12
then
$$\theta$$_steam -$$\theta$$_ice =180.12

Is this really correct?

Thanks!

 

[Jhero]

Yes, this is correct. The temperature interval between the steam point and the ice point is 180.12 on this scale. This scale is known as the Rankine scale, where the ice point is assigned a value of 492 and the steam point is assigned a value of 671.12. This scale is commonly used in thermodynamics and is based on absolute zero being assigned a value of 0. Therefore, the temperature interval between the ice point and the steam point is 180.12 degrees on this scale.