- #71
harrylin
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Tracer said:I am not sure of what your point is here. But let me put some values on a sample problem so you can see if I am doing something illogical or my math is wrong.
A. Let the ships speed through the wind equal to 15 meters/sec directly fore to aft.
B. Let the rim velocity of the wheel be 10 meters/sec and its direction of rotation is such that the rim velocity adds to the ship’s wind velocity at the top of the wheel and subtracts from the ship’s wind velocity at the bottom of the wheel.
C. Let the rain drops fall vertically at 30 meters/sec when the wind velocity is zero. This will be treated as an unknown until it has been calculated based on its viewed angle of approach to the observer.
At the top of the wheel the wind velocity will be 25 meters/sec. If the angle of incidence (theta)to the observer at the top of the wheel is 50.194429 degrees, then the true vertical velocity of the rain drops is:
V = 25tan(theta)=25tan(50.194429) =25(1.2) = 30 meters/sec
The rain drops will strike the observer at the top of the wheel at:
V = 30/sin(theta) = 30/0.7682213 = 39.051248 meters/sec
At the bottom of the wheel the wind velocity will be -5 meters/sec. if theta at the bottom of the wheel is measured to be -80.537678 degrees, then the true vertical velocity of the rain drops is:
-5tan(theta) =-5tan(-80.537678) = -5(-6) = 30 meters/sec
The rain drops will strike the observer at the bottom of the wheel at:
V = 30/sin(theta) =30/0.9863939 = 30.413813 meters/sec
Is this correct? What can be determined from composite measurements from the top and the bottom of the wheel?
As you indicate, here the rain drop velocity is around 30 m/s relative to the guy in the giant wheel (note that this is also called closing speed), but it depends on the ship's velocity and varies over time (sorry: I did not check your calculations but it looks fine).
My point was, and still is: he doesn't know these rain drop velocities relative to him. Apparently you think/thought that it is but one velocity which he should be able to determine from the wheel's speed and the difference of observed angles (theta is in fact the angle between one inclination and the other one). Did you try if he can indeed achieve that feat?
Harald
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