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I made this point earlier in the thread. As the cutoff momentum k increases to infinity, the Planck mass goes to infinity. The Planck mass runs as k, and the S&W paper shows that it is asymptotically proportional to k.
All that MP means is the low energy Planck mass. In the asymsafe picture, MP(k) is the physically relevant Planck mass at scale k and it is scale dependent. At high energies, the low energy Planck mass is not relevant to black hole/particle physics. The physical Planck energy goes to infinity, so what does "transplanckian" particle collision mean? (The word "transplanckian gets thrown around not always thoughtfully or with clear significance.)
Newton constant is even more strongly scale dependent. It goes to zero as 1/k2. I mentioned that in a post quite a few days back.
This is why I regard some of the old (say 1995-2003) discussion of "transplanckian" particle collisions forming black holes as unconvincing.
And even more dubious was the talk about "asymptotic darkness", but happily one hears very little about that nowadays. People were theorizing way beyond their base of solid understanding.
I see no indication that the obsolete discussion took the running of Newton's constant into account. What we have nowadays is a growing suspicion that gravity has an RG fixed point, and IF IT DOES, as many numerical studies now indicate it does, then G(k) falls off as 1/k2.
The Shaposhnikov paper can even tell you the proportionality. So how is a black hole supposed to form? According to the asymsafe assumption gravity is essentially turned off at very high energy density, or at very high momentum transfer (q in the S&W paper) if we are discussing particle collisions.
So there is no indication that what the earlier authors had to say fits into OUR discussion which takes seriously the possibility that gravity is asymptotically safe and that the Renormalization Group plays an important role.
All that MP means is the low energy Planck mass. In the asymsafe picture, MP(k) is the physically relevant Planck mass at scale k and it is scale dependent. At high energies, the low energy Planck mass is not relevant to black hole/particle physics. The physical Planck energy goes to infinity, so what does "transplanckian" particle collision mean? (The word "transplanckian gets thrown around not always thoughtfully or with clear significance.)
Newton constant is even more strongly scale dependent. It goes to zero as 1/k2. I mentioned that in a post quite a few days back.
This is why I regard some of the old (say 1995-2003) discussion of "transplanckian" particle collisions forming black holes as unconvincing.
And even more dubious was the talk about "asymptotic darkness", but happily one hears very little about that nowadays. People were theorizing way beyond their base of solid understanding.
I see no indication that the obsolete discussion took the running of Newton's constant into account. What we have nowadays is a growing suspicion that gravity has an RG fixed point, and IF IT DOES, as many numerical studies now indicate it does, then G(k) falls off as 1/k2.
The Shaposhnikov paper can even tell you the proportionality. So how is a black hole supposed to form? According to the asymsafe assumption gravity is essentially turned off at very high energy density, or at very high momentum transfer (q in the S&W paper) if we are discussing particle collisions.
So there is no indication that what the earlier authors had to say fits into OUR discussion which takes seriously the possibility that gravity is asymptotically safe and that the Renormalization Group plays an important role.
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