Struggling with a Limit: Help Appreciated!

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The limit in question is lim(X->0) 1/(ix)*(exp(imx) - 1). The user attempted various methods, including L'Hôpital's rule and expanding the exponential, but was unsuccessful. Another participant confirmed that L'Hôpital's rule is applicable since both the numerator and denominator approach zero as x approaches zero. They clarified the differentiation process and concluded that the limit evaluates to m, as the exponential term approaches one. The discussion emphasizes the importance of careful differentiation in limit calculations.
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I can't get the following limit to work:

lim(X->0) 1/(ix)*(exp(imx) - 1 ) = m

I'm sorry for the poor notation. I tried expanding the exponential, and L'hopitals rule and combinations of these approaches, but i can't get it to work out. Any help is much appreciated!
 
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student111 said:
I can't get the following limit to work:

lim(X->0) 1/(ix)*(exp(imx) - 1 ) = m

I'm sorry for the poor notation. I tried expanding the exponential, and L'hopitals rule and combinations of these approaches, but i can't get it to work out. Any help is much appreciated!

I assume you mean \lim_{x\fo 0}\frac{e^{imx}- 1}{ix}. I can see no reason why L'Hopital's rule would not work:

Both e^{imx}-1 and ix go to 0 as x goes to 0.

\left(e^{imx}\right)'= I am e^{imx} while (ix)'= i. By L'Hopitals rule, the limit is the same as \lim_{x\to 0}\frac{im e^{imx}}{i}= m\left(\lim_{x\to 0}e^{imx}\right)= m.
 
doh! I differentiated the whole part instead of nominator and denominator separately..

Thx alot
 
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