Surface Area of Shoe Box Shape to Maximize Volume

AI Thread Summary
To maximize the volume of a shoe box made from a 3 feet by 4 feet cardboard, squares of side length x are cut from each corner. The dimensions of the resulting box are expressed as length L = 4 - 2x, width W = 3 - 2x, and height H = x. The volume V is calculated using the formula V = L * W * H. The goal is to determine the outside surface area of the box while maximizing this volume.
JuliusDarius
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Homework Statement


Imagine you have a rectangular piece of cardboard measuring 3 feet by 4 feet. You know that if you cut a square out of each corner, you can fold the pieces together and tape them together to make an object that looks like a shoe box:http://www.omahamathtutor.com/wp-content/uploads/2012/03/shoebox.png
What is the outside surface area of this shoe box shape that maximize the volume?



Homework Equations


2ab + 2bc + 2ac


The Attempt at a Solution


Not sure where to start
 
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V = L*W*H

Then express the length, width, and height in terms of x after you remove those four squares from the 4 x [STRIKE]12[/STRIKE] 3 rectangle.
 
Last edited:
Bohrok said:
V = L*W*H

Then express the length, width, and height in terms of x after you remove those four squares from the 4x12 rectangle.

Could you show me how to do that?
 
The length is originally 4, then you cut off two segments of length x from both ends of that side, so L = 4 - 2x. Same thing for the width.

After cutting out the four squares, you have four flaps that fold up; what would be the height of these flaps?
 
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