Table Functions Explained: Help for Understanding

[OMGMathPLS]

I do not get what is going on here. Can someone please explain? This is sohard for me to understand. thank you
View attachment 3546

 

[MarkFL]

Let's look at the first place where an answer is expected, that is to find $g(-2)$.

We are given the rule:

\(\displaystyle g(x)=f(-x)+1\)

Therefore, we may state:

\(\displaystyle g(-2)=f(-(-2))+1=f(2)+1=-1+1=0\)

Can you try the others in the same way?

 

[OMGMathPLS]

Let's look at the first place where an answer is expected, that is to find $g(-2)$.

We are given the rule:

\(\displaystyle g(x)=f(-x)+1\)

Therefore, we may state:

\(\displaystyle g(-2)=f(-(-2))+1=f(2)+1=-1+1=0\)

Can you try the others in the same way?

Ok so we're including the - we are plugging it in with the negative.
That makes more sense.

 

[MarkFL]

Ok so we're including the - we are plugging it in with the negative.
That makes more sense.

Yes, the rule:

\(\displaystyle g(x)=f(-x)+1\)

tells us to take the input to $g$, change its sign or negate it, and input it to $f$, and then add 1 to that output, and this is the output of $g$. :D

 

[OMGMathPLS]

so he next values I got were: 0,1,0, -1

 

[MarkFL]

Let's look at the next one...what did you do to get 0?

 

[OMGMathPLS]

Let's look at the next one...what did you do to get 0?

I'm not sure why we are putting it into the (x) first and then = f(x) if we're trying to find g(x).

Because all we are using from the table is the x so why are we do we even need the f(x)?

 

[MarkFL]

I'm not sure why we are putting it into the (x) first and then = f(x) if we're trying to find g(x).

In order to find $g(x)$, we need to use the given rule:

\(\displaystyle g(x)=f(-x)+1\)

So, we do the following:

1.) Negate the input to $g$.

2.) Pass this negated input to $f$.

3.) Add 1 to the value obtained from $f$.

4.) This is the value of $g$.

So, for the second one, we find:

1.) \(\displaystyle -(-1)=1\)

2.) \(\displaystyle f(1)=2\)

3.) \(\displaystyle 2+1=3\)

4.) \(\displaystyle g(-1)=3\)

Or, as I did the first one:

\(\displaystyle g(-1)=f(-(-1))+1=f(1)+1=2+1=3\) :D

 

[OMGMathPLS]

In order to find $g(x)$, we need to use the given rule:

\(\displaystyle g(x)=f(-x)+1\)

So, we do the following:

1.) Negate the input to $g$.

2.) Pass this negated input to $f$.

3.) Add 1 to the value obtained from $f$.

4.) This is the value of $g$.

So, for the second one, we find:

1.) \(\displaystyle -(-1)=1\)

2.) \(\displaystyle f(1)=2\)

3.) \(\displaystyle 2+1=3\)

4.) \(\displaystyle g(-1)=3\)

Or, as I did the first one:

\(\displaystyle g(-1)=f(-(-1))+1=f(1)+1=2+1=3\) :D

Thank you