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Aikenfan
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Tackling Homework Equations - A Step-by-Step Guide
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The discussion focuses on understanding homework equations related to optics, specifically the behavior of funhouse mirrors and image inversion. It emphasizes the importance of ray diagrams for visualizing how images are formed, suggesting that this skill is essential for solving related problems. The conversation also touches on personal experiences with mirrors, highlighting the humorous aspect of encountering unusual mirror placements. Overall, the thread aims to clarify concepts of magnification and image formation in non-standard mirrors. Mastery of these principles is crucial for tackling homework equations effectively.
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denverdoc
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check here: http://www.glenbrook.k12.il.us/gbssci/phys/class/refln/u13l3e.html
which of the cases do you suppose it will be?
which of the cases do you suppose it will be?
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Aikenfan
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It would be upside down?
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denverdoc
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no. My point was funhouse mirrors do not typically invert the image, maybe you never been to one, so look to that case for an answer to your question re magnification. Its always better to be able to do the ray diagrams, but from your other post, I see that this might not be a skill you have yet.
Hehe-I now remember the last time I had seen other than a plane mirror--it was strategically located at waist height just above the toilet. Very gratifying place to relieve oneself.
Hehe-I now remember the last time I had seen other than a plane mirror--it was strategically located at waist height just above the toilet. Very gratifying place to relieve oneself.
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Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears.
My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it.
I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height.
But the...
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