I would assume they mean the tension at the instant after cutting the other string.stuc said:
Hm ... could be. I didn't interpret it that way but I guess that could be right. stuc, my comments are not based on that assumption.haruspex said:
...the tension at the instant after cutting the other stringharuspex said:
Hmm.. that does not fit with either interpretation. But I remain of the view that it's the instantaneous value they're after.stuc said:
there is no weight given.haruspex said:
learn but always confuse when try to solve itphinds said:
What is the definition of a Newton?stuc said:there is no weight given.
1N = the force needed to accelerate 1kg of massphinds said:
You got 4.33 N for the upward component of force contributed by each wire. But there are two wires. So what is the weight of the object? If this weight has to be supported by only one wire, what would the tension in that wire have to be?stuc said:
haruspex said:
weight of the mass = 7.071NChestermiller said:
No, that doesn't work. Pythagoras applies when two vectors at right angles are to be added.stuc said:
haruspex said:
..tq for the info..will be calculateHint: you already calculated it in post #12.stuc said:
In this figure, the 5 N should be the hypotenuse, not one of the other sides. You're using the wrong triangle.stuc said:
haruspex said:
i get W=8.66N ..but how the answer is 5NChestermiller said:
Steady on, so far all we have found is the hanging weight. The tension in one string immediately after the other is cut might be different. So leave the weight in the form ##10\sin(60)N## for now.stuc said:i get W=8.66N ..but how the answer is 5N
haruspex said:
After a rope is cut, the system is no longer stable. There will be an acceleration. The forces in the vertical direction will no longer balance.stuc said:
if one of the ropes have been cut, it mean the object just hang VERTICALLY with one rope with 10sin(60)N load on it.Is it my assumption is correct?haruspex said:
Not immediately. Although the question does not make it completely clear, I am very confident that you are supposed to find the tension in the remaining rope the instant after one rope is cut. You can take the remaining rope and the mass as being in exactly the same positions as before, and, for the instant, stationary. But now there is a nonzero acceleration.stuc said:
haruspex said:
Yes, it's wrong. (That would be the right answer if the angle were 45 degrees.)stuc said:
haruspex said:
stuc said:
haruspex said:
The free body diagram is right, but you need to think about which way the acceleration must be. In your force analysis, you have summed the vertical components and assumed the total to be zero. In other words, you have supposed the acceleration to be horizontal. Clearly it will not be. Which way will it be?stuc said:
A rope tension mystery refers to a situation where the tension in a rope cannot be easily determined or is unexpected. This can occur due to various factors such as the weight of the object being lifted, the angle of the rope, and the type of rope being used.
To solve a rope tension mystery, you need to use the principles of physics and engineering. This involves calculating the forces acting on the rope, considering the properties of the rope and the objects it is supporting, and using equations such as Newton's laws of motion to determine the tension in the rope.
The weight of the object being lifted, the angle of the rope, the type and condition of the rope, and any external forces such as wind or friction can all affect the tension in a rope. Other factors may include the length and thickness of the rope, the method of attachment, and the surface the rope is resting on.
There are several methods for measuring rope tension, including using a tension meter, a dynamometer, or a load cell. These devices can provide a numerical value for the tension in the rope, but it is important to also consider other factors that may affect the tension, such as those mentioned above.
Solving rope tension mysteries has practical applications in various industries, such as construction, engineering, and transportation. For example, understanding the tension in cables and ropes used in bridges and cranes is crucial for ensuring their structural integrity and safety. It can also be useful in everyday situations, such as setting up a hammock or securing a load on a truck or trailer.