- #1
billtodd
- 137
- 33
I am trying to understand how would one opt to solve this open problem?, if there are some objects in the non-constructive-axiomatic QFT which mathematically are ill-defined.
One such ill defined notion is of virtual particles.
I tried to understand what constitutes a virtual particle. For example we have photons that are real which don't have mass as opposed virtual photons that do have mass. And then there are gluons which appear to be all of them virtual, and none are "real"; What does that mean?
Ok, I think I understand it now; It seems according to Wiki, that a virtual particle has mass that it's off-shell vs a real particle which its mass is on-shell, i.e. one satisfies the following relation: ##E^2=(pc)^2-(mc^2)^2## which is on shell and the other doesn't satisfy this.
Well I was under the impression that on-shell satsifies: ##m^2=-k^2## and off-shell doesn't, or vice versa.
Anyway, why can't a gluon also have a real partner, I read in Google that gluons only come as virtual particles and they have zero mass; But then are they on-shell or off-shell?
One such ill defined notion is of virtual particles.
I tried to understand what constitutes a virtual particle. For example we have photons that are real which don't have mass as opposed virtual photons that do have mass. And then there are gluons which appear to be all of them virtual, and none are "real"; What does that mean?
Ok, I think I understand it now; It seems according to Wiki, that a virtual particle has mass that it's off-shell vs a real particle which its mass is on-shell, i.e. one satisfies the following relation: ##E^2=(pc)^2-(mc^2)^2## which is on shell and the other doesn't satisfy this.
Well I was under the impression that on-shell satsifies: ##m^2=-k^2## and off-shell doesn't, or vice versa.
Anyway, why can't a gluon also have a real partner, I read in Google that gluons only come as virtual particles and they have zero mass; But then are they on-shell or off-shell?