The electric field of infinite sheets

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The discussion focuses on the electric field between an infinite sheet of uniform positive charge and an infinite, uncharged conducting sheet. It is explained that the positive charge induces a uniformly distributed negative charge on the side of the conductor facing the charged sheet, while a positive charge appears on the outer surface of the conductor. This arrangement results in an electric field of zero inside the conducting sheet, as the induced charges cancel the field from the charged sheet. The consistency with Gauss's law is highlighted, confirming that the electric field lines terminate at the induced negative charge and re-emerge from the positive charge on the opposite surface. Overall, the induced charge distribution effectively neutralizes the electric field within the conductor.
Conservation
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I am trying to understand electric fields of conductors.

Say that there is an infinite sheet of uniform positive charge; parallel to it lies a infinite, uncharged conducting sheet. What would the field look like between the sheets? Beyond the sheets? I would guess that the uniformly charged sheet would induce a uniformly distributed negative charge on the conducting sheet on the side closer to it, but I don't understand how the induced positive charge would distribute itself in the conducting sheet. Or how the positive charge would then affect the field.

Thanks.
 
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Conservation said:
but I don't understand how the induced positive charge would distribute itself in the conducting sheet. Or how the positive charge would then affect the field.
It will be on the other surface(outer surface, far from the sheet) of the conducting sheet. These induced charges will make the E field inside the conducting sheet 0. Electric field lines from the charged sheet will terminate at the -ve induced charge on the conducting sheet and will reappear from the +ve induced charge on the other surface of the conducting sheet.
 
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Okay. That makes sense; That would make E field coming out from the opposite surface same as the E field going in, and that's consistent with Gauss's law.

What I fail to see is how this distribution of induced charges will result a field of 0 inside the conductor. If there is an infinite positive surface charge on one side of the conducting sheet and infinite negative surface charge on the other side of the conducting sheet, shouldn't there be a field inside the conducting sheet?
 
Conservation said:
shouldn't there be a field inside the conducting sheet?
Yes. And that field exactly cancels the field due to the charged sheet, making net E field inside the conducting sheet zero. This is why electric field inside a conductor placed in an external electric field is always 0.
 
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