The first and second law of thermodynamics

AI Thread Summary
The first law of thermodynamics states that the energy input into a system equals the energy output when a complete cycle occurs. In contrast, the second law emphasizes that to obtain useful work, the energy input must exceed the energy output, indicating that some energy is always lost as waste heat. This means that while energy is conserved, achieving practical work requires additional energy beyond what is returned. Therefore, no energy conversion process can be 100% efficient. Understanding these laws clarifies the relationship between energy conservation and the necessity of additional energy for useful work.
jamesd2008
Messages
63
Reaction score
0
In my thermodynamics book it states that the first law is,

" When a system undergoes a complete cycle the net heat supplied plus the net work input is zero"

And then it states that for the second law,

"In any complete cycle the gross heat supplied plus the net work input must be greater than zero"

Are these not contradicting each other or am I miss understanding the gross and net aspects? Could someone please help me try to understand?

Thanks in advance
James
 
Engineering news on Phys.org
The first law, as you have quoted, is pretty much saying "the energy you put in must be equal to the energy you get back out again".

The second law says "while the first law still applies, to get something useful out, you need to put the same amount in, plus a bit more".

The Wikipedia article is pretty good.
 
Thats great thanks for your input, So although the energy is conserved, to gain practical useful work extra heat is needed?
 
jamesd2008 said:
Thats great thanks for your input, So although the energy is conserved, to gain practical useful work extra heat is needed?

That is correct. In other words, you can never have an energy conversion device or process which is 100% efficient.
 
I have Mass A being pulled vertically. I have Mass B on an incline that is pulling Mass A. There is a 2:1 pulley between them. The math I'm using is: FA = MA / 2 = ? t-force MB * SIN(of the incline degree) = ? If MB is greater then FA, it pulls FA up as MB moves down the incline. BUT... If I reverse the 2:1 pulley. Then the math changes to... FA = MA * 2 = ? t-force MB * SIN(of the incline degree) = ? If FA is greater then MB, it pulls MB up the incline as FA moves down. It's confusing...
Hi. I noticed that all electronic devices in my household that also tell time eventually lag behind, except the ones that get synchronized by radio signal or internet. Most of them are battery-powered, except my alarm clock (which runs slow as well). Why does none of them run too fast? Deliberate design (why)? Wrong temperature for quartz crystal? Decreasing battery voltage? Or just a coincidence?
Back
Top