The magnetic phase change of an electromagnetic wave during reflection

In summary, the question discussed the use of ##E_\bot## and ##\overrightarrow{B}=\dfrac{1}{v}\widehat{k}\times \overrightarrow{E}## to determine the direction of the magnetic field. However, the question only mentioned ##E_\bot##, which is not enough information. The change in ##\overrightarrow{B}## also depends on the change in ##\overrightarrow{E_\parallel}##, as shown in the equation ##\overrightarrow{B}=\dfrac{1}{v}\widehat{k}\times \left( \overrightarrow{E}_{\parallel}+\overrightarrow{E}_{\bot}\right)##. The attached
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Dom Tesilbirth
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Homework Statement
An electromagnetic wave is incident on a water-air interface. The phase of the perpendicular component of the electric field, ##E_\bot##, of the reflected wave into the water is found to remain the same for all angles of incidence. By what angle does the phase of the magnetic field H change?
Relevant Equations
$$\overrightarrow{B}=\dfrac{1}{v}\widehat{k}\times \overrightarrow{E}$$
If the question had mentioned ##\overrightarrow{E}## instead of ##E_\bot##, then we could have used ##\overrightarrow{B}=\dfrac{1}{v}\widehat{k}\times \overrightarrow{E}## to get the direction of the magnetic field. But the question had only mentioned ##E_\bot##. To my understanding, knowing ##E_\bot## is not enough. Because, according to ##\overrightarrow{B}=\dfrac{1}{v}\widehat{k}\times \overrightarrow{E}=\dfrac{1}{v}\widehat{k}\times \left( \overrightarrow{E}_{\parallel}+\overrightarrow{E}_{\bot}\right)##, the change in ##\overrightarrow{B}## also depends on the change in ##\overrightarrow{E_\parallel}##.Is there any other way to solve this problem?
 
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