The T dS equations and Sackur-Tetrode equation

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The discussion focuses on the application of the TdS equations and the Sackur-Tetrode equation in thermodynamics. The user expresses confusion regarding part (e) of a problem, particularly in relating the expressions for entropy change (dS) to the isothermal process. They highlight the need to correctly apply limits when comparing the left and right sides of the equation, specifically using initial and final volumes. The conversation emphasizes the importance of integrating and understanding the relationship between entropy and volume changes. Overall, the thread addresses common misconceptions in thermodynamic equations and their applications.
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The "T dS" equations and Sackur-Tetrode equation

Homework Statement



This is a bit of a dumb question (I hope)

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I'm having trouble with part (e).

The Attempt at a Solution



to show it for (a), dS is given, so T\times{NK_bln{\frac{V_f}{V_i}} = P\times{dV} since dU = 0 for isothermal process. P can be written as \frac{NK_bT}{V}, but this is clearly not equal to what I got in part A... although it would be if I integrated the right side (?)
 
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The TdS equation has TdS on the left hand side, you have an expression for \Delta S of a process with a macroscopic change. Do you know that
d(\ln{x})=\frac{d(\ln{x})}{dx}dx =\frac{dx}{x}
?
 


Was I wrong to assume that \Delta{S} = dS?
 


Yes, if you use Vf and Vi on the left hand side, you need to use them on the right hand side and take the limit
\lim_{V_{f}\rightarrow V_{i}}
on both sides and show that the ratio of the left hand side to the right hand side approaches 1, but it's much easier to just use the relation I mentioned.
 

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