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Since you like nit-picking: The result is picture-independent, but the formula used to write it down was not. In a picture-dependent form I'd have needed to write ##\langle A(t)\rangle_t## since both the operator and the state may depend on time. The Heisenberg picture needs less complicated notation.vanhees71 said:If a result is dependent on the picture of the time evolution, it doesn't describe anything physical. It's not something related to what can be observed (by definition of standard QT).