Thermodynamics lab: Heat Engine Examination

AI Thread Summary
The discussion revolves around calculating the power, efficiency, and air-to-fuel ratio for a heat engine based on provided data. Key parameters include torque, exhaust temperature, ambient temperature, fuel temperature, volumetric flow rate of air, fuel pressure, and calorific value of the fuel. A participant expressed confusion about calculating the mass flow rate of fuel and initially misinterpreted the speed measurement. Clarification revealed that the speed referred to mass flow rate in liters per minute, not shaft speed. The participant received assistance and ultimately gained a clearer understanding of the calculations involved.
CptJackWest
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Homework Statement


Calculate the Power, Efficiency, air to fuel ratio.

torque-3.809Nm
speed-3137.207 l/min
T1 Temperature Exhaust=412.598degC
T2 Temperature Ambient=19.141degC
T3 Temperature Fuel=18.994degC
dv/dt Volumetric Flow Air=109.954 l/min
p fuel Fuel Pressure= 21.475 mbar
calorific value of fuel= 435kj/kg

The only thing I am not sure on is how to calculate the mass flow rate of the fuel.
no formula is given, but tried Q=m(T2-T1) but I don't know Q. any help or tips would be great.
Cheers
Jack
 
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You have speed as 3137.207 l/min. Speed of what? Are these units correct?
 
Thanks for helping.
This problem is from an experiment we did involving an engine.The speed was to stated but I am taking it as the speed of the shaft in the engine. That units that i wrote is what is the data sheet I was given. I did not like the look of them either, but I am now assuming that it in meters per minute.
 
If you measured the speed of an operating engine with a tachometer, then 3137 is more likely measured in revolutions per minute (RPM).
 
Thanks for the help, my teacher ended up explaining the whole thing to me and it is now a lot clearer. The speed was not the speed but the mass flow rate in litres per min.
Thanks a lot for trying to help.
cheers
 
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