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Homework Statement
The masses of these particles are mA = 379 kg, mB = 500 kg, and mC = 140 kg. d1 = 0.558 m and d2 = 0.279 m. Calculate the magnitude of the net gravitational force acting on particle A
(Attached Diagram of Particles.)
Homework Equations
F=Gm1m2/r^2
G=6.673x10^-11Nm^2/kg^2
The Attempt at a Solution
The question asks what is the magnitude of the g force acting on particle A. So, I added the masses of particles b and c.
Particle B and C = 640kg
F = (6.673x10^-11)(379kg)(640kg)/(0.558m+0.279m) = (0.0000162)/(0.701)= 0.0000231N (WRONG)
Then I thought particle C has no effect on the force of particle A so I just used the mass of particle A and B.
F=(6.673x10^-11)(379)(500)/(0.558)^2 = (0.0000126)/(0.346) = 0.0000364N
Then I added the Force from A-B and Force B-C...
Fa-b=0.0000364N
Fb-c=(6.673x10^-11)(500)(140)/(0.279)^2 = 0.0000600N
Therefore, 0.0000364N+0.0000600N=Fnet=0.0000964N
Can anyone help?
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