- #141
JesseM
Science Advisor
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- 16
JesseM said:Huh? What do you mean when you say "it will take [itex]\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}[/itex] seconds, measured in that same frame, to reach the observer"? First of all, the time dilation formula [tex]t' = t*\sqrt{1 - v^2/c^2}[/tex] is normally understood purely in terms of relating the time between ticks in the clock's rest frame to the time between ticks in the frame of an observer moving relative to the clock, the idea that it should have something to do with the time for the light of a tick to reach an observer moving relative to the clock as measured in the clock's own rest frame appears to be an idea unique to you.
But to say the observer "passed the clock at the start of the tick" is too vague, this only works if you specifically assume the observer was passing the top mirror at the moment the light was departing from the bottom of the clock; the time to reach the observer would be zero if the observer was passing the bottom at the moment light was departing from there, and somewhere in between zero and the time you give if he was passing the middle. And even if we add in the qualification that you are talking about the time for light from the bottom to reach the observer who passes the top at the moment the light was emitted, I don't really see the point of this calculation--the time for the light from the bottom of the clock to reach the observer has nothing to do with the time the observer will judge for the light clock to make one tick in his own rest frame, and thus nothing to do with the time dilation equation (you could after all place the observer in a completely different position than next to the top mirror when light is emitted from the bottom, in which case the time for the light from the bottom to reach him would be different, but it wouldn't change his judgement about the time of one tick of that light clock in his own frame).Grimble said:If the clock's time is one second, the height is ct where t=1, the horizontal distance is vt' and the diagonal distance is ct', where t' is the time for the light to reach the observer who passed the clock at the start of the 'tick' all measured in the clock's frame, then [tex]{t^'}= \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}[/tex] by the application of simple old Pythagoras.