Time intervals measured by stationary and moving observers

In summary, the paper discusses how time intervals are perceived differently by stationary and moving observers, highlighting the principles of time dilation and the relativity of simultaneity as described in Einstein's theory of relativity. It explains that for stationary observers, time is measured uniformly, while moving observers experience time at a slower rate relative to their stationary counterparts. This leads to variations in the measurement of time intervals depending on the relative motion between observers, fundamentally altering the understanding of time in physics.
  • #36
Hak said:
Thank you. Yes, I wrote ##L' (v'^2)## instead of ##L'(v^2)##, right?
The switching was in defining ##x = v^2## and ##a = v'^2## instead of the other way around.
 
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  • #37
PeterDonis said:
That's because they're not fine if you have already chosen the unprimed reference frame.

I still cannot understand this. I would be grateful if you could explain it again in a way that I can understand it. Thank you very much for your contribution.
 
  • #38
PeterDonis said:
Obviously not, because in post #21 you switched reference frames (you didn't realize that's what you were doing when you said ##x = v^2##, ##a = v'^2##, but it was).
I guess I didn't really understand. So you can change the frame of reference, but you can't reverse ##x## and ##a##, right?
 
  • #39
Hak said:
I would be grateful if you could explain it again in a way that I can understand it.
I'm not sure what more I can say. When you define ##x = v'^2##, ##a = v^2##, you are choosing the unprimed frame. That's just a fact. There is no "explanation" for it. So if you say ##x = v^2##, ##a = v'^2##, that is inconsistent with choosing the unprimed frame. What more is there to say?
 
  • #40
Hak said:
So you can change the frame of reference, but you can't reverse ##x## and ##a##, right?
Wrong. Reversing ##x## and ##a## is changing the frame of reference. But then you have to start the whole analysis over from the beginning. You can't just reverse them in one equation, that was obtained by a series of approximations that assumed you were using the unprimed frame.
 
  • #41
PeterDonis said:
When you define ##x = v'^2##, ##a = v^2##, you are choosing the unprimed frame. That's just a fact. There is no "explanation" for it. So if you say ##x = v^2##, ##a = v'^2##, that is inconsistent with choosing the unprimed frame. What more is there to say?
I did not understand what calculations I should have done to choose the primed frame of reference. Should I change all the calculations in the unfolding to do that? Thank you very much.
 
  • #42
Hak said:
I did not understand what calculations I should have done to choose the primed frame of reference. Should I change all the calculations in the unfolding to do that?
See post #40.
 
  • #43
@PeterDonis Thank you so much for everything, I think I understand. You really gave me a great amount of help. Thank you again.
 
  • #44
Hak said:
@PeterDonis Thank you so much for everything, I think I understand. You really gave me a great amount of help. Thank you again.
You're welcome! :smile:
 

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