Time period of a conical pendulum by D'Alembert's principle

AI Thread Summary
The discussion focuses on deriving the time period of a conical pendulum using D'Alembert's principle, starting with the equation T = 2π√(r/(g tanθ)). The user struggles with incorporating the vertical component of acceleration, as the virtual displacement does not include the z-direction, which is essential for including the gravitational term. Suggestions are made to consider virtual displacements in the θ direction and to use Cartesian coordinates to apply the constraints of the system effectively. It is emphasized that while θ remains constant for the specific case, D'Alembert's principle allows for considering any virtual displacement that adheres to the system's constraints. The conversation highlights the importance of correctly applying the principle to arrive at the desired result.
justwild
Messages
52
Reaction score
0

Homework Statement


Finding the time period of a conical pendulum by D'Alembert's principle. The string is of a constant length and all dissipations are to be ignored.

Homework Equations


The time period of a conical pendulum is 2\pi \sqrt{\frac{r}{g\tan\theta}}. I need to arrive at this result starting from the D'Alembert's principle.

The Attempt at a Solution


I assume a cylindrical coordinates system whose origin coincides with the fulcrum of the pendulum. Thus, for the conical pendulum with constant string length, the acceleration of the particle would be
\ddot{\vec{r}}=\ddot{\rho}\hat{\rho}+\rho\ddot{\phi}\hat{\phi}.
Now the virtual displacement can be given as
\delta\vec{r}=\rho\delta\phi\hat{\phi}.
And the force acting on the particle as \vec{F}=-mg\hat{z}.

Now if I substitute all these in the D'Alembert's principle, I won't be able to calculate the time period from there. This is obvious because the virtual displacement does not contain the \hat{z} term and due to the dot product, the expression won't include any g term which is necessary because the result does contain the g term.
I am out of ideas for now and I would appreciate anyone from the PF helping me out.
 
Physics news on Phys.org
Hello, justwild.

What about virtual displacements in the ##\hat{\theta}## direction. For acceleration in spherical coordinates see here.
 
TSny said:
What about virtual displacements in the ##\hat{\theta}## direction.
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?
 
justwild said:
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?

Yes, for the particular solution that you are considering θ will remain constant. However, in http://en.wikipedia.org/wiki/D'Alembert's_principle]d'Alembert's[/PLAIN] principle you can consider any virtual displacement that doesn't violate the physical constraint of the system.
 
Last edited by a moderator:
  • Like
Likes 1 person
Use Cartesian co-ordinates. Take the length of the string=constant to be the constraint eq. Find delta(z).
Substitute values in d'alemberts', put delta (z).
You'll be able to find the time period
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top