Tips for Expressing 8 cos^2 x -6 sin x cos x +2 in rcos(2x+α)+s Form

  • Thread starter kingboy
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In summary, the conversation discusses how to express the expression 8 cos^2 x -6 sin x cos x +2 in the form rcos (2x+α)+s and determine the value of the constants. The conversation also mentions finding the greatest and latest values of the expression as x varies, and suggests using trigonometric identities such as cos2x = 2cos2x - 1 to solve the problem.
  • #1
kingboy
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Homework Statement



show that the expression 8 cos^2 x -6 sin x cos x +2 may be expressed in the form rcos (2x+α)+s ,and determine the value of the constants r,s and α.hence ,or otherwise, find the greatest and latest values of the expression as x varies.

Homework Equations



cos 2x=cos^2x-sin^2x ,sin2a=2 sinxcosx ,acos x-bsinx=rcos(x+α)

The Attempt at a Solution


8 cos^2 x -6 sin x cos x +2=8(cos 2x+sin^2x)+3(2 sinxcosx)+2=?
 
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  • #2
hi kingboy! :smile:

(try using the X2 icon just above the Reply box :wink:)
kingboy said:
cos 2x=cos^2x-sin^2x

learn all your trignonmetric identiies …

in this case, more useful would be cos2x = 2cos2x - 1 :wink:
 
  • #3
tiny-tim said:
in this case, more useful would be cos2x = 2cos2x - 1 :wink:

agreed :D
 

FAQ: Tips for Expressing 8 cos^2 x -6 sin x cos x +2 in rcos(2x+α)+s Form

What is the purpose of expressing 8 cos^2 x -6 sin x cos x +2 in rcos(2x+α)+s form?

The purpose of expressing a trigonometric equation in the form of rcos(2x+α)+s is to simplify the equation and make it easier to solve. This form allows us to easily identify the amplitude, period, and phase shift of the trigonometric function.

How do you convert 8 cos^2 x -6 sin x cos x +2 to rcos(2x+α)+s form?

To convert the equation, we use the identities cos^2 x = 1/2(1+cos2x) and sin x cos x = 1/2 sin2x. This will give us the form rcos(2x+α)+s, where r is the amplitude, α is the phase shift, and s is the vertical shift.

What is the amplitude of the trigonometric function in rcos(2x+α)+s form?

The amplitude is the value of r in the equation rcos(2x+α)+s. In this case, the amplitude would be the square root of the coefficient of cos2x, which is 8. Therefore, the amplitude is √8 or 2√2.

How do you find the period of the trigonometric function in rcos(2x+α)+s form?

The period of a trigonometric function in this form is given by the formula 2π/|2| = π. This means that the period is π units. In other words, the function will repeat itself every π units.

What is the phase shift of the trigonometric function in rcos(2x+α)+s form?

The phase shift is represented by the value of α in the equation rcos(2x+α)+s. To find the phase shift, we set 2x+α=0 and solve for x. In this case, α=0 and there is no phase shift, meaning the graph of the function will not be shifted horizontally.

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