Torque on Shaft w/ 1000 kg Load & 35 mpm Wire Speed

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    Shaft Torque
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The discussion focuses on calculating the torque on a shaft when lifting a 1000 kg load with a winch at a wire speed of 35 meters per minute. Participants reference the formulas T = Fr for torque and P = Fv for power, emphasizing the need to determine force (F), velocity (v), and radius (r) for accurate calculations. The required horsepower for the electric motor, operating at 980 RPM with a 70:1 gearbox ratio, is also a key point of inquiry. Users are encouraged to engage actively and adhere to forum rules for effective problem-solving. Understanding these calculations is essential for proper winch operation and motor selection.
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What is the torque on a shaft when applying a load of 1000 kgs. through winch lifting at a speed of 35 meters per minute wire speed. What should be the H.P of an electric motor if it runs the winch. The motor rpm is 980. Gear box speed ratio is 70:1.
 
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PF expects users to put in some effort, check out the forum rules.

Are you familiar with T =Fr ?
Or an answer can be had more directly via:
P=Fv
 
What is F, v and r in the formula. I am not familiar.
 
Force, velocity and radius.
 

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