Total spin quantum number of helium atom with 2 electrons in first shell

AI Thread Summary
The total spin quantum number of a helium atom with two electrons in the first shell (1s) is determined by the Pauli exclusion principle, which requires the electrons to have opposite spins, resulting in a total electronic spin of 0. However, this does not represent the overall spin of the atom, which includes contributions from electronic spin, nuclear spin, and orbital angular momentum. The discussion clarifies that while the z-component of the electronic spin is zero, the total spin can still be non-zero, as the spins of two spin-1/2 particles can combine to form either an S=0 or S=1 state. Understanding the addition of angular momentum in quantum mechanics is essential for accurately determining the total spin. The conversation highlights the importance of distinguishing between total electronic spin and atomic spin.
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Homework Statement



A helium atom had two electrons in the first shell (1s). Explain, withour detailed derivation, what the value of the total spin quantum number is.

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The Attempt at a Solution



Since the 2 electrons are in the first (1s) shell they must have opposite spins, +1/2, and -1/2 due to pauli exclusion principle. The total spin must be their sum +1/2-1/2=0. Therefore the atom spin is 0? Can atoms have spin 0?
 
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A couple of misconceptions:

1) That's not the spin of the atom. The spin of the atom is the sum of the electronic spin, the nuclear spin, and the orbital angular momentum. (There's no reason the spin of an atom can't be 0.)

2) You've shown that the z-component of the total electronic spin is 0. You haven't shown that the total spin is 0. It's possible, for instance, that the electrons are in the S=1, mS=0 state.

I'm guessing the problem isn't asking about the atom's spin but just the total electronic spin. When you have two spin-1/2 particles, their spins can combine to form an S=0 or S=1 state. You need to explain why one of them is not allowed.
 
vela said:
A couple of misconceptions:

1) That's not the spin of the atom. The spin of the atom is the sum of the electronic spin, the nuclear spin, and the orbital angular momentum. (There's no reason the spin of an atom can't be 0.)

2) You've shown that the z-component of the total electronic spin is 0. You haven't shown that the total spin is 0. It's possible, for instance, that the electrons are in the S=1, mS=0 state.

I'm guessing the problem isn't asking about the atom's spin but just the total electronic spin. When you have two spin-1/2 particles, their spins can combine to form an S=0 or S=1 state. You need to explain why one of them is not allowed.

I asked the proffesor and he said the same, that the answer was just for the z-axis, he didn't explain. Why is this for the z-axis? Is the total spin just the sum of all the spins? But we don't know the nuclear spin etc?
 
You need to go back and review the addition of angular momentum in quantum mechanics. This is a fundamental topic in quantum mechanics that you need to know. In particular, you should be able to apply the concepts to two spin-1/2 particles to find their total angular momentum.
 
thanks
 
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