Trig, find tan A and tan B (no numbers given)

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To find tan A and tan B in a right triangle with sides a = t, b = k, and hypotenuse p, the tangent ratios can be expressed as tan A = t/k and tan B = k/t. The discussion highlights that without specific values for t and k, the tangents cannot be definitively calculated, as they depend on the lengths of the sides. The relationship tan A = 1/tan B is also established, indicating the reciprocal nature of the tangent functions in right triangles. Ultimately, the conclusion is that the ratios are the most informative aspect given the lack of numerical values. Understanding these relationships is key to solving similar problems in trigonometry.
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Homework Statement



Find tan A, tan B

I have a right angle triangle. Length a = t, length b = k, hypotenuse = p.

The Attempt at a Solution



Usually I would just use the normal rule of \tan a =\frac{opp}{adj} but how can I get an answer here? I can't just say \tan a =\frac{t}{k} because this makes no sense.

The only thing I can think of is say the answer is 1. Or tan a = 45, tan b = 45.
 
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If this is really all you were given, then that is all you can do. The answer cannot possibly be 1 because there is nothing in the problem barring you from making t=2 and k=1, making tan A = 2 (indeed, you could fix it so tan A = any number you want).
 
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Question 6 is the one relating to my original question.
 
Seems to me like all you can do it get the quotients you gave in the first post :)
 
I think your teacher was trying to get you to show that

tanA = 1/tanB

tanA = t/k

tanB = k/t
 
Chestermiller said:
I think your teacher was trying to get you to show that

tanA = 1/tanB

tanA = t/k

tanB = k/t

This. :wink:
 

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