Trying to find volume given Newtons/ archimedes principle

AI Thread Summary
To find the volume of a paperweight using Archimedes' principle, the difference in weight between air and water is calculated, revealing a weight of displaced water at 2.6 N. This weight is then converted to mass by dividing by the acceleration due to gravity (9.81 m/s²), resulting in a mass of 0.265 kg. The volume is determined by dividing this mass by the density of water (1000 kg/m³), yielding a volume of 2.65E-4 m³. The calculations illustrate the relationship between weight, mass, and volume in fluid mechanics. Understanding these principles is essential for solving similar physics problems.
bc1170
Messages
2
Reaction score
0

Homework Statement



A paperweight, when weighed in air, has a weight of W = 6.6 N. When completely immersed in water, however, it has a weight of Win water = 4.0 N. Find the volume of the paperweight.


Homework Equations



Fb = Wfluid


The Attempt at a Solution



I can find density using density of object/density of water=weight of object/initial weight-immersed weight

but can not seem to find out how to find volume... I am stuck
 
Physics news on Phys.org
The difference between the two weights is the weight of the displaced water, isn't it? What volume of water has a weight of 2.6N?
 
I am not sure.. I know that Newtons are kg/s^2 I just don't know how it relates in any way to volume
 
Newton's are kg*m/s^2. They are a unit of force. They have the same units as m*a (in F=ma). Volume relates to mass through density. Mass relates to force through weight equals mg (m is mass and g is the acceleration of gravity). You might want to review some of these topics.
 
The nitty gritty of it is as follows.
the Difference of the weight in the air, and the weight in the water equals weight of the object
Therefore, we use the following steps to find the volume of the object.

Step 1)
6.6 N -4.0 N = 2.6 N <--weight of water displaced

Step 2)
Divide by gravity to get mass of object
2.6 N / 9.81 m/s^2 = .265kg <-- mass of object

Step 3)
Take that and divide by the density of water
.265kg / 1000kg/m^3 = 2.65E-4 m^3 <--equals the volume of the object
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top