MHB Understanding an Equation: $\frac {1}{2\sqrt{2}} = \frac{\sqrt2} {4}$

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The equation $\frac{1}{2\sqrt{2}} = \frac{\sqrt{2}}{4}$ is validated through multiple methods of simplification. By manipulating the left side, it can be expressed as $\frac{2}{4\sqrt{2}}$, which further simplifies to $\frac{\left(\sqrt{2}\right)^2}{4\sqrt{2}}$ and ultimately results in $\frac{\sqrt{2}}{4}$. Additionally, rationalizing the denominator confirms the equality by multiplying by $\frac{\sqrt{2}}{\sqrt{2}}$, leading to the same result. Both approaches demonstrate that the two fractions are indeed equivalent.
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On the board, the professor made a note that:

$$\frac {1}{2\sqrt{2}}$$ is equal to

$$\frac{\sqrt2} {4}$$

I don't see how this is. Can someone explain this? I've tried to work it out a few ways.
 
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Note that

$$\frac{1}{2\sqrt{2}} = \frac{2}{4\sqrt{2}} = \frac{\left(\sqrt{2}\right)^2}{4\sqrt{2}} = \frac{\sqrt{2}}{4}$$
 
He rationalized the denominator:

$$\frac{1}{2\sqrt{2}}=\frac{1}{2\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{4}$$
 
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