Understanding the Electric Field in a Circular Arrangement of Charges

  • Thread starter Thread starter electromania
  • Start date Start date
  • Tags Tags
    Field
AI Thread Summary
Arranging an infinite number of charges in a circle does not result in a zero electric field everywhere within that circle. Unlike a uniform spherical shell of charge, the electric field inside a circular arrangement of charges is not uniformly zero. In a conducting material, however, the electric field is zero due to the charges redistributing on the outer surface. This redistribution occurs because the electric field within the conducting material must be zero under electrostatic conditions. Therefore, while the electric field is zero inside the conductor, it is not zero within the circle formed by the charges.
electromania
Messages
2
Reaction score
0
If you arrange infinite amount of charges in a circle, will the electric field anywhere within the circle be zero?
 
Physics news on Phys.org
electromania said:
If you arrange infinite amount of charges in a circle, will the electric field anywhere within the circle be zero?
No. The field within a uniform circle of charge is not zero everywhere, as it would be within a uniform spherical shell of charge.
 
But why is the electric field in a circular conductor always zero, aren't the charges arranged in the same way?
 
electromania said:
But why is the electric field in a circular conductor always zero,
Under electrostatic conditions, the field within the conducting material itself will be zero, no matter what the shape of the conductor.
aren't the charges arranged in the same way?
Say you have a conducting wire in the shape of a circle, which you charge. The charge will arrange itself on the outer surface of the conductor such that the electric field within the material will be zero. But inside the circle is not part of the conducting material. The field within the circle will not necessarily be zero.
 
Thread ''splain this hydrostatic paradox in tiny words'
This is (ostensibly) not a trick shot or video*. The scale was balanced before any blue water was added. 550mL of blue water was added to the left side. only 60mL of water needed to be added to the right side to re-balance the scale. Apparently, the scale will balance when the height of the two columns is equal. The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL). So where does the weight of the remaining (550-60=) 490mL go...
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Back
Top