Understanding the Focal Plan of Parallel Light Through a Thin Lens

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Parallel light entering a thin lens at an angle θ focuses on the focal plane due to the principles of ray transfer matrix analysis. The mathematical proof involves using the product of the thin lens matrix and the free space propagation matrix, with the thin lens matrix positioned on the right, reflecting the sequence of interaction. This approach reveals that the resulting matrix has an element A=0, indicating focusing behavior. Consequently, all rays reach the focal plane at equal heights, confirming they are effectively focused. Understanding this concept is crucial for applications in optics and lens design.
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Why does parallel light focus on the focal plan when enters a thin lens at an angle θ?
How to proof that mathematically?
 
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brianeyes88677 said:
Why does parallel light focus on the focal plan when enters a thin lens at an angle θ?
How to proof that mathematically?

Does the Thin Lens page at wikipedia help? http://en.wikipedia.org/wiki/Thin_lens

:smile:
 
I need the proof that the parallel light isn't perpendicular to the lens.
 
The proof can easily be done using the ray transfer matrices. In case you are not familiar with this term yet, navigate to this http://en.wikipedia.org/wiki/Ray_transfer_matrix_analysis
In describing focusing of a collimated beam (parallel rays) using such matrices, one uses the matrix product between thin lens matrix and free space propagation matrix in the order that the thin lens matrix is on the right. This order corresponds to the encounter of the ray bundle with the lens first, then propagate further behind it to reach the focal plane. The resulting matrix have the element A=0. This kind of ray transfer matrix is termed as having focusing behavior, and you will see at the end of your calculation that the heights of all rays at the focal plane are equal, which physically means they are being focused.
 

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