- #36
PeterDonis
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In fact, I can sharpen this by considering the case ##\kappa = 2## [Edit: should be sqrt(2), see post #54], for which the metric is competely symmetric in ##x## and ##t##: [Edit: this is incorrect, see post #54]PeterDonis said:Saying that, in a chart with ##|\kappa| > 1##, an observer moving along a timelike line that is an integral curve of ##\partial / \partial x## can have his clock read the same forever, while an observer moving along a timelike line that is an integral curve of ##\partial / \partial t## can't, because the latter is a case of "spatially coincident causality" but the former is not, seems nonsensical to me. Both coordinates are timelike in this chart, so both sets of curves define valid worldlines for observers, and neither set of observers is privileged physically over the other.
$$
ds^2 = -dt^2 - dx^2 - 2 dx dt + dy^2 + dz^2
$$
Now which coordinate counts as "spatially coincident"?
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