Understanding Tidal Forces & Rindler Metric

In summary, the statements in this conversation do not seem to be entirely self-consistent. However, tidal forces are equivalent to curved spacetime, the curvature tensor of the Rindler metric is zero, and the gravitational field is not a tensor in GR.
  • #71
My own view on the EP not only on Rindler wedge but in any spacetime with a vanishing Riemann tensor but non-vanishing Christoffel symbols is briefly stated in Papaetrou's book "Lectures on General Relativity" at page 56:

When there are gravitational accelerations present, as for example in the
gravitational field of the earth, the space cannot be the flat Minkowski space. Indeed,
in the Minkowski space we can have

[tex]\Gamma^{\alpha}_{\mu\nu}=0,[/tex]

everywhere. This should then be interpreted as meaning that the sum of the inertial
and the gravitational acceleration could be made equal to zero everywhere. This does,
however, not correspond to our experience about gravitational accelerations: When
gravitational accelerations exist, it is not possible to make them vanish everywhere.
We can only make them vanish at one point, or approximately in a small region, by the
use of an appropriate coordinate system. Therefore, when a gravitational field is
present, the space will be necessarily a curved Riemannian space.

But since the spacetime is flat and yet there we have non-vanishing Christoffel symbols, there must be a coordinate transformation that does make the these symbols vanish and this is what happens to be true on the Rindler wedge when events can finid co-pairs in the Minkowski spacetime everywhere, leading to the fact that on Rindler wedge the EP is valid overally!

AB
 

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