Unit conversion inside a derived gausses law eq

AI Thread Summary
The discussion revolves around converting the unit \(\alpha = \frac{15 \text{ cm} \cdot \text{m}^3}{\mu \text{C}}\) into meters per coulomb. The user struggles with unit conversions, specifically how to handle the centimeter to meter conversion and the microcoulomb to coulomb conversion. They attempt various calculations but are unsure about their results, particularly the expression \(1.5 \times 10^{-7} \text{ m}^4/\text{C}\). The confusion stems from the complexity of the units involved, and the user expresses frustration over the problem's difficulty. Ultimately, the user seeks clarity on the correct conversion method.
bobasp1
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Homework Statement


Essentially I'm working out a problem and I am given \alpha = \frac{15cm\bullet m^{3}}{\mu C}
and I need to get it in just terms of meters/coulombs

I'm having a real tough time with weird unit conversions like this.

Homework Equations



1m = 100cm 1 micro coulomb = 1 X 10^-6 coulombs

The Attempt at a Solution


1m/100cm * 10^-6 micro c/1c * the above eq. 1.5 x 10^-7 m^4/C pretty sure that isn't correct.Thanks
 
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15 cm*m^3/micro C* 1Micro C/1X10^6 C *1 m/ 100 cm
 
bobasp1 said:
1m/100cm * 10^-6 micro c/1c * the above eq. 1.5 x 10^-7 m^4/C pretty sure that isn't correct.

Thanks

the 10^-6 of micro coulomb will become 10^6 when it goes up
 
and whatsthat m^3 with 15cm
 
RTW69 said:
15 cm*m^3/micro C* 1Micro C/1X10^6 C *1 m/ 100 cm
bahh >__< i had it right, I guess my problem isn't correct then Thanks everyone

1.5e-7 m^4/C
cupid.callin said:
and whatsthat m^3 with 15cm

no clue why, its from quest homework service and the problem it self is pretty chill, but that one variable is screwing with me.
 
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