- #281
- 24,775
- 792
thomson scattering cross-section of electron
earlier I was making lists of like a dozen or so basic constants
that are used so much they are worth remembering
the REALLY basic constants are all one, in this system, so they are not hard to remember
but then there is the next layer, like the mass of the electron is 2.1E-22 mass units
even that is not so bad because the rest-energy of the electron is the same number...2.1E-22 energy units.
and the Compton wavelength is just the reciprocal of that
1/(2.1E-22) length units.
well there is something called the "Classical Radius of the Electron"
which is just 1/137 times the Compton.
so it is something I can calculate just from knowing 1/137 and 2.1E-22
and the THOMSON crosssection which tells the probability that an electron left to its own devices will scatter some light is simply
[tex]\sigma_{\text{Thomson}} = \frac{8\pi}{3}(\text{classical radius})^2[/tex]
I am having trouble getting the LaTex to work so for redundancy I will just type out what I was trying to write
sigma-sub-Thomson = 8pi/3 x (classical radius)2
once you have the thomson crosssection then (as that U. Texas link shows) you have to tack on a term that shows how the resonant frequency of the molecule affects the scattering probability, but the basic thing that there is any scattering at all comes from the Thomson, which is just 8pi/3 times the square of the classical radius.
It isn't important but I might as well calculate the thomson scattering crosssection
the radius is
1/(137 x 2.1E-22) = 3.48E19 natural length units
squaring and multiplying by 8pi/3 gives
1.01E40 natural area units.
wow. that is weird. the interaction of an electron with light is a little area which in these units comes out to right around E40 area units.
just as a check I converted that to metric and it was about 6.6E-29 sqmeters. wow again. that is what the U.Texas website on this gives!
getting the answer their conventional way involves looking up constants and multiplying a lot of stuff together because the formulas are more complicated but comes to the same thing.
earlier I was making lists of like a dozen or so basic constants
that are used so much they are worth remembering
the REALLY basic constants are all one, in this system, so they are not hard to remember
but then there is the next layer, like the mass of the electron is 2.1E-22 mass units
even that is not so bad because the rest-energy of the electron is the same number...2.1E-22 energy units.
and the Compton wavelength is just the reciprocal of that
1/(2.1E-22) length units.
well there is something called the "Classical Radius of the Electron"
which is just 1/137 times the Compton.
so it is something I can calculate just from knowing 1/137 and 2.1E-22
and the THOMSON crosssection which tells the probability that an electron left to its own devices will scatter some light is simply
[tex]\sigma_{\text{Thomson}} = \frac{8\pi}{3}(\text{classical radius})^2[/tex]
I am having trouble getting the LaTex to work so for redundancy I will just type out what I was trying to write
sigma-sub-Thomson = 8pi/3 x (classical radius)2
once you have the thomson crosssection then (as that U. Texas link shows) you have to tack on a term that shows how the resonant frequency of the molecule affects the scattering probability, but the basic thing that there is any scattering at all comes from the Thomson, which is just 8pi/3 times the square of the classical radius.
It isn't important but I might as well calculate the thomson scattering crosssection
the radius is
1/(137 x 2.1E-22) = 3.48E19 natural length units
squaring and multiplying by 8pi/3 gives
1.01E40 natural area units.
wow. that is weird. the interaction of an electron with light is a little area which in these units comes out to right around E40 area units.
just as a check I converted that to metric and it was about 6.6E-29 sqmeters. wow again. that is what the U.Texas website on this gives!
getting the answer their conventional way involves looking up constants and multiplying a lot of stuff together because the formulas are more complicated but comes to the same thing.
Last edited: