Vant Hoff factor problem. General chem 2

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The van't Hoff factor for KCl is 1.85, and the boiling point elevation can be calculated using the formula ΔTb = Kb x m x i, where Kb is 0.51 and m is 0.50 m. The calculation yields an increase in boiling point of 0.47175°C, but this value must be added to the original boiling point of water (100°C) to find the new boiling point. The common mistake noted in the discussion is forgetting to add the calculated increase to the boiling point of water. Therefore, the correct final boiling point should be 100.47175°C.
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The van't Hoff factor for KCl is i= 1.85. What is the boiling point of a 0.50 m solution of KCl in water? For water, Kb = 0.51.

I have the equation which i believe is (Delta Tb)= Kb x m x i ??


m= molality... = .50 m
Kb is given 0.51
i is given 1.85


I have to have 5 sig figs and the answer i get is .47175, but that's not right supposedly. What I'm I doing wrong?
 
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Are they asking for the increase in the boiling point...or the NEW boiling point? The formula you have gives you the increase but you have to add the number you get to the original boiling point. So here you would add your answer to the boiling point of water. Common mistake people forgetting the last step...
 

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