Velocity and kinetic energy of a neutron

AI Thread Summary
The discussion focuses on calculating the velocity and kinetic energy of a neutron with a given wavelength of 0.2 nm. Initial calculations incorrectly suggested a velocity exceeding the speed of light, prompting a reevaluation using the de Broglie relation, which yielded a corrected velocity of approximately 1.98 x 10^3 m/s. The corresponding kinetic energy was calculated to be about 0.0205 eV. Comparatively, this energy is 46.1% less than the average kinetic energy of a gas molecule at room temperature. The final results were confirmed as accurate by participants in the discussion.
carus88
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Calculate the velocity and kinetic energy of a neutron (mass 1.675x10-27kg) that has a wavelength of 0.2nm. How does this compare to the average kinetic energy of a gas molecule at room temperature (0.038eV at 200C)?

1. E=mc^2

2. KE = 1/2 mv^2

I used 1. to calculate the energy which was 1.51 x10^-10 J

Then i subbed the energy into 2. and got a velocity of 4.24 x10^8 m/s

LOL obviously I'm going wrong some where how can a neutron be going faster than light!

CAN SOMEONE HELP PLEASE?
 
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The energy you are computing is the rest energy, not the kinetic energy. To get the velocity use the de Broglie relation between wavelength and momentum. Then use that velocity to compute the kinetic energy.
 
sorry bout the multiple post i don't know how to delete the other one?

i used :

1. lambda=h/p=h/mv

an got v to = 1.98x10^3 m/s

then used ke = 0.5mv^2 = 0.0205eV

are these answers correct?

i attampted the the 2nd part and worked out a percentage
based on the respective energies an that the neutron had 46.1% less energy than the molecule
 
Looks right to me.
 
Thank you for your help.
 
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